ГДЗ: Упражнение 2.344 — Нахождение дроби от числа / Математика 6 класс. Часть 1

\(\frac{9}{52}\) · \(\frac{13}{3}\) · \(\frac{1}{3}\) = \(\frac{1}{4}\);
(\(\frac{11}{3}\) + \(\frac{14}{5}\)) · \(\frac{60}{97}\) = \(\frac{97}{15}\) · \(\frac{60}{97}\) = 4;
\(\frac{5}{36}\) · \(\frac{9}{5}\) = \(\frac{1}{4}\). Сумма: \(\frac{1}{4}\) + 4 + \(\frac{1}{4}\) = \(4\,\frac{1}{2}\).

\(\frac{5}{9}+\frac{1}{5}=\frac{34}{45}\); \(28\frac{6}{7}-19\frac{5}{14}=\frac{19}{2}\). Тогда \(\frac{34}{45}·\frac{19}{2}·\frac{9}{17}=\frac{19}{5}\), и \(\frac{19}{5}-\frac{1}{5}=\frac{18}{5}=3\frac{3}{5}\). Ответ: \(3\frac{3}{5}\).