ГДЗ: Упражнение 4.370 — Свойства действий с рациональными числами / Математика 6 класс. Часть 2

\((5):(7)=\frac{5}{7}\); \((4)+(\frac{5}{7})=\frac{33}{7}\); \((\frac{99}{10})+(\frac{33}{7})=\frac{1023}{70}\); \((\frac{1023}{70})-(\frac{39}{10})=\frac{75}{7}\); \((3):(7)=\frac{3}{7}\); \((2)+(\frac{3}{7})=\frac{17}{7}\); \((\frac{75}{7})-(\frac{17}{7})=\frac{58}{7}\).

Ответ: \(\frac{58}{7}\).

\((1):(6)=\frac{1}{6}\); \((2)+(\frac{1}{6})=\frac{13}{6}\); \((5):(11)=\frac{5}{11}\); \((5)+(\frac{5}{11})=\frac{60}{11}\); \((\frac{13}{6})-(\frac{60}{11})=-\frac{217}{66}\); \((-\frac{217}{66})-(\frac{21}{2})=-\frac{455}{33}\); \((1):(3)=\frac{1}{3}\); \((7)+(\frac{1}{3})=\frac{22}{3}\); \((-\frac{455}{33})+(\frac{22}{3})=-\frac{71}{11}\).

Ответ: \(-\frac{71}{11}\).

\((11):(18)=\frac{11}{18}\); \((5)+(\frac{11}{18})=\frac{101}{18}\); \((7):(24)=\frac{7}{24}\); \((\frac{101}{18})-(\frac{7}{24})=\frac{383}{72}\); \((3):(18)=\frac{1}{6}\); \((4)+(\frac{1}{6})=\frac{25}{6}\); \((\frac{383}{72})-(\frac{25}{6})=\frac{83}{72}\); \((5):(24)=\frac{5}{24}\); \((3)+(\frac{5}{24})=\frac{77}{24}\); \((\frac{83}{72})-(\frac{77}{24})=-\frac{37}{18}\); \((1):(18)=\frac{1}{18}\); \((2)+(\frac{1}{18})=\frac{37}{18}\); \((-\frac{37}{18})+(\frac{37}{18})=0\).

Ответ: \(0\).

\((4):(5)=\frac{4}{5}\); \((3)+(\frac{4}{5})=\frac{19}{5}\); \((\frac{19}{5})-(\frac{8}{5})=\frac{11}{5}\); \((1):(3)=\frac{1}{3}\); \((2)+(\frac{1}{3})=\frac{7}{3}\); \((\frac{11}{5})-(\frac{7}{3})=-\frac{2}{15}\); \((-\frac{2}{15})+(\frac{16}{5})=\frac{46}{15}\); \((\frac{46}{15})+(\frac{2}{5})=\frac{52}{15}\); \((7):(15)=\frac{7}{15}\); \((1)+(\frac{7}{15})=\frac{22}{15}\); \((\frac{52}{15})+(\frac{22}{15})=\frac{74}{15}\).

Ответ: \(\frac{74}{15}\).