ГДЗ: Упражнение 2.210 — Действия сложения и вычитания смешанных чисел / Математика 6 класс. Часть 1

\(\frac{37}{3}\) − \(\frac{45}{4}\) = \(\frac{148}{12}\) − \(\frac{135}{12}\) = \(\frac{13}{12}\).

14 − \(\frac{143}{15}\) = \(\frac{210}{15}\) − \(\frac{143}{15}\) = \(\frac{67}{15}\).

\(\frac{13}{12}\) + \(\frac{67}{15}\) = \(\frac{65}{60}\) + \(\frac{268}{60}\) = \(\frac{111}{20}\).

Ответ: \(5\,\frac{11}{20}\).

15 − \(\frac{101}{8}\) = \(\frac{120}{8}\) − \(\frac{101}{8}\) = \(\frac{19}{8}\).

\(\frac{27}{2}\) − \(\frac{101}{9}\) = \(\frac{243}{18}\) − \(\frac{202}{18}\) = \(\frac{41}{18}\).

\(\frac{19}{8}\) − \(\frac{41}{18}\) = \(\frac{171}{72}\) − \(\frac{164}{72}\) = \(\frac{7}{72}\).

Ответ: \(\frac{7}{72}\).

\(\frac{44}{3}\) − \(\frac{50}{9}\) = \(\frac{132}{9}\) − \(\frac{50}{9}\) = \(\frac{82}{9}\).

\(\frac{31}{8}\) + \(\frac{29}{6}\) = \(\frac{93}{24}\) + \(\frac{116}{24}\) = \(\frac{209}{24}\).

\(\frac{82}{9}\) − \(\frac{209}{24}\) = \(\frac{656}{72}\) − \(\frac{627}{72}\) = \(\frac{29}{72}\).

\(\frac{43}{4}\) − \(\frac{40}{9}\) = \(\frac{387}{36}\) − \(\frac{160}{36}\) = \(\frac{227}{36}\).

\(\frac{29}{72}\) + \(\frac{227}{36}\) = \(\frac{29}{72}\) + \(\frac{454}{72}\) = \(\frac{161}{24}\).

Ответ: \(6\,\frac{17}{24}\).

\(\frac{103}{7}\) − 14 = \(\frac{103}{7}\) − \(\frac{98}{7}\) = \(\frac{5}{7}\).

30 − \(\frac{208}{7}\) = \(\frac{210}{7}\) − \(\frac{208}{7}\) = \(\frac{2}{7}\).

\(\frac{5}{7}\) + \(\frac{2}{7}\) = 1.

\(\frac{22}{7}\) − \(\frac{23}{28}\) = \(\frac{88}{28}\) − \(\frac{23}{28}\) = \(\frac{65}{28}\).

1 + \(\frac{65}{28}\) = \(\frac{28}{28}\) + \(\frac{65}{28}\) = \(\frac{93}{28}\).

Ответ: \(3\,\frac{9}{28}\).