В ABC стороны \(5\,\frac{1}{12}\) см, \(6\,\frac{1}{5}\) см, \(4\,\frac{1}{6}\) см. Найдите периметр.
\(\frac{61}{12}\) + \(\frac{31}{5}\) = \(\frac{305}{60}\) + \(\frac{372}{60}\) = \(\frac{677}{60}\).
\(\frac{677}{60}\) + \(\frac{25}{6}\) = \(\frac{677}{60}\) + \(\frac{250}{60}\) = \(\frac{309}{20}\).
Ответ: \(15\,\frac{9}{20}\).
Периметр \(15\,\frac{9}{20}\) см.