ГДЗ: Упражнение 2.202 — Сравнение, сложение и вычитание обыкновенных дробей / Математика 6 класс. Часть 1

\(\frac{1821}{50}\) · \(\frac{1}{10}\) = (1821 · 1)/(50 · 10) = \(\frac{1821}{500}\).

\(\frac{1821}{500}\) − \(\frac{249}{250}\) = \(\frac{1821}{500}\) − \(\frac{498}{500}\) = \(\frac{1323}{500}\).

Ответ: 2,646.

\(\frac{6977}{100}\) · \(\frac{29}{5}\) = (6977 · 29)/(100 · 5) = \(\frac{202333}{500}\).

\(\frac{6967}{100}\) · \(\frac{29}{5}\) = (6967 · 29)/(100 · 5) = \(\frac{202043}{500}\).

\(\frac{202333}{500}\) − \(\frac{202043}{500}\) = \(\frac{29}{50}\).

\(\frac{29}{50}\) + \(\frac{21}{50}\) = 1.

(1) : (\(\frac{2}{5}\)) = \(\frac{5}{2}\).

Ответ: 2,5.

\(\frac{1293}{100}\) + \(\frac{6547}{100}\) = \(\frac{392}{5}\).

\(\frac{317}{1000}\) + \(\frac{1583}{1000}\) = \(\frac{19}{10}\).

\(\frac{392}{5}\) · \(\frac{19}{10}\) = (392 · 19)/(5 · 10) = \(\frac{3724}{25}\).

\(\frac{131}{25}\) − \(\frac{189}{50}\) = \(\frac{262}{50}\) − \(\frac{189}{50}\) = \(\frac{73}{50}\).

\(\frac{7}{2}\) · \(\frac{73}{50}\) = (7 · 73)/(2 · 50) = \(\frac{511}{100}\).

\(\frac{3724}{25}\) − \(\frac{511}{100}\) = \(\frac{14896}{100}\) − \(\frac{511}{100}\) = \(\frac{2877}{20}\).

Ответ: 143,85.

600 + 138 = 738.

214538 − 738 = 213800.

Ответ: 213800.